3-(x-5)^2=(2-x)(2+x)+1

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Solution for 3-(x-5)^2=(2-x)(2+x)+1 equation: 



3-(x-5)^2=(2-x)(2+x)+1

We move all terms to the left:

3-(x-5)^2-((2-x)(2+x)+1)=0

We add all the numbers together, and all the variables

-(x-5)^2-((-1x+2)(x+2)+1)+3=0

We multiply parentheses ..

-((-1x^2-2x+2x+4)+1)-(x-5)^2+3=0



We calculate terms in parentheses: -((-1x^2-2x+2x+4)+1), so:

(-1x^2-2x+2x+4)+1

We get rid of parentheses

-1x^2-2x+2x+4+1

We add all the numbers together, and all the variables

-1x^2+5

Back to the equation:

-(-1x^2+5)



We get rid of parentheses

1x^2-(x-5)^2-5+3=0

We add all the numbers together, and all the variables

x^2-(x-5)^2-2=0

We move all terms containing x to the left, all other terms to the right

x^2-(x-5)^2=2

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